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2/21/2014 4:27:18 PM
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I have figured out a math formula!

It's for finding the power of a number to the second power. For example, 12x12=144 to find 13x13 you just add 13 and 12 and add it to 12 to the 2nd power. So 12x12=144 13+12=25 144+25=169 13x13=169 It works!
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  • Edited by Bolt: 2/21/2014 5:40:27 PM
    Obvious Part [quote] X*X=A X+Y=B Y*Y=C Y=X+1 [/quote] Interesting Part [quote] A+B=C [/quote] X*X+X+Y=C X*X+X+X+1=C (X^2)+2X+1=C (Where C is the square of the of X+1) (X^2)+2X+1=(X+1)(X+1) It's a parabolic function with a root at negative one, but other than that I can't find anything really substantive about it. I vaguely recall using a property similar to this for an iterating loop in Matlab once, but if that's what this is then it's one of the many things Euler pointed out. I'm not familiar enough with whatever theory is applicable to this to say anything more about the possible significance. It could possibly be useful though if you needed to tell a code to find the square above a given value and you didn't want to just put (n+1)^2 for some reason (maybe n is defined symbolically and ^2 would take more computation time than your method in a given scenario). Kind of neat though.

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  • As Silent already pointed out, it works because the whole n^2+(n+1)+n can be separated into factors (n+1)^2. I had never noticed that before, pretty neat. Could be good for impressing people with squaring big numbers in your head.

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  • TrollFace It works!

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  • What??

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  • repostan because i want someone that's good at math to explain why this happens [quote]I found something interesting today too. On the graph of the equation f(x)=x^sin(x), each maximum on x>0, and each minimum on x<0, have equal x and y values. I felt pretty proud of that discovery while my teacher droned on about integrating logarithms.[/quote]

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