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originally posted in: Need geometry help!
3/5/2013 11:38:02 PM
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I can approximate this using Calculus, I just need a little more information. What are the lengths from G to C and G to B?
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  • I've been assuming that point G is the center of a circle, so lines GB and GC are 26'.

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  • Very well, I just figure I would ask, the diagram makes it look a bit like an oval. The equation for a circle is x^2 + y^2 = r^2, the radius r in this case being 26'. We can then solve this to find the equation y = squareroot(26^2 - x^2) = squareroot(676 - x^2) Now all we have to do is take an integral of our function for y to figure out the area underneath the circle, and we'll bound it from -20 (the length of DG) to 26 (the length of GC). I'll spare you the algorithmic steps of the integral, but the answer comes out to approximately 993.703 square (feet? I'm actually not sure what the ' thingies stand for >_>)

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  • I think he wants the area enclosed by the shape |ABCEJHD|, i.e. the area between the two circle lines. So just take the value you got for your integral and subtract (pi)(10^2)/2 from it.

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  • >_> I should actually read the questions.

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  • Attempt marks =P

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