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11/23/2014 7:46:19 PM
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Anti-tank rifles do exist; they knock out the treads and vital machinery of tanks, and are capable of penetrating their armor. The human sniper rifle in Halo for example is one.
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In real life a .50 cal rifle was designed and intended to defeat LIGHT ARMORED VEHICLES. Tanks are heavy armor. (I'm not yelling with the caps) there is a 25mm rifle designed to knock out treads though.
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Ah I see. The original calculation said 50 cal anti-tank. Now I'm not sure which it is, probably somewhere in the middle.
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A 50 caliber bullet is actually .50 caliber, this means that the BULLET itself has a diameter of .50 inches. And a 9mm bullet is 9mm in diameter. The standard 9mm handgun fires a 9x19mm bullet the 19mm refers to the length of the CARTRIDGE as a whole (tip of bullet to base of cartridge), lots of guns are the same caliber or mm but have different overall cartridges. A good example is the standard NATO 7.62mm(.308 cal)x 51mm compared to the soviet rounds of 7.62x39(AK) and 7.62x54R (RPK,PKC,PKM, and Dragunov) R means rimmed, the cartridge has a lip or rim around the base. Or an Army M107 rifle uses a 12.7x99mm (.50 Browning Machine Gun BMG) round and a pistol uses a 12.7x33mm(.50 Action Express AE). Without the decimal point a 50 cal rifle would be shooting a bullet almost six foot in diameter(non-existent) plus tanks have very thick armor and use reactive armor, large steel boxes mounted to the exterior filled with 30 pounds of C-4 plastic explosives each. The science of this is that a large outward explosion will defeat a smaller incoming explosion or bullet. Please understand that I am NOT being smug or condescending or argumentative. As a former U.S.A. Sniper, I enjoy talking ballistics and putting out good information. Hope this helps.
